16x^2-8x+6=5

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Solution for 16x^2-8x+6=5 equation: 



16x^2-8x+6=5

We move all terms to the left:

16x^2-8x+6-(5)=0

We add all the numbers together, and all the variables

16x^2-8x+1=0

a = 16; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{32}=1/4$

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